2(y+2)=5(y-4)

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Solution for 2(y+2)=5(y-4) equation: 



2(y+2)=5(y-4)

We move all terms to the left:

2(y+2)-(5(y-4))=0

We multiply parentheses

2y-(5(y-4))+4=0



We calculate terms in parentheses: -(5(y-4)), so:

5(y-4)

We multiply parentheses

5y-20

Back to the equation:

-(5y-20)



We get rid of parentheses

2y-5y+20+4=0

We add all the numbers together, and all the variables

-3y+24=0

We move all terms containing y to the left, all other terms to the right

-3y=-24

y=-24/-3

y=+8

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