(3/5)y+(2/5)=

Solution for (3/5)y+(2/5)= equation:

(3/5)y+(2/5)=

We move all terms to the left:

(3/5)y+(2/5)-()=0


Domain of the equation: 5)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+3/5)y+(+2/5)-()=0

We add all the numbers together, and all the variables

(+3/5)y+(+2/5)=0

We multiply parentheses

3y^2+(+2/5)=0

We get rid of parentheses

3y^2+2/5=0

We multiply all the terms by the denominator


3y^2*5+2=0

Wy multiply elements

15y^2+2=0

a = 15; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·15·2
Δ = -120
Delta is less than zero, so there is no solution for the equation