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5=(3x+3)/6
We move all terms to the left:
5-((3x+3)/6)=0
We multiply all the terms by the denominator
-((3x+3)+5*6)=0
We calculate terms in parentheses: -((3x+3)+5*6), so:We get rid of parentheses
(3x+3)+5*6
We add all the numbers together, and all the variables
(3x+3)+30
We get rid of parentheses
3x+3+30
We add all the numbers together, and all the variables
3x+33
Back to the equation:
-(3x+33)
-3x-33=0
We move all terms containing x to the left, all other terms to the right
-3x=33
x=33/-3
x=-11
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