59c+42=5c+6(7+9c)

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Solution for 59c+42=5c+6(7+9c) equation: 



59c+42=5c+6(7+9c)

We move all terms to the left:

59c+42-(5c+6(7+9c))=0

We add all the numbers together, and all the variables

59c-(5c+6(9c+7))+42=0



We calculate terms in parentheses: -(5c+6(9c+7)), so:

5c+6(9c+7)

We multiply parentheses

5c+54c+42

We add all the numbers together, and all the variables

59c+42

Back to the equation:

-(59c+42)



We get rid of parentheses

59c-59c-42+42=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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