35=7(2x+1)

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Solution for 35=7(2x+1) equation:



35=7(2x+1)
We move all terms to the left:
35-(7(2x+1))=0
We calculate terms in parentheses: -(7(2x+1)), so:
7(2x+1)
We multiply parentheses
14x+7
Back to the equation:
-(14x+7)
We get rid of parentheses
-14x-7+35=0
We add all the numbers together, and all the variables
-14x+28=0
We move all terms containing x to the left, all other terms to the right
-14x=-28
x=-28/-14
x=+2

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