59=(2x-1)+(3x+2)+(2x-5)

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Solution for 59=(2x-1)+(3x+2)+(2x-5) equation: 



59=(2x-1)+(3x+2)+(2x-5)

We move all terms to the left:

59-((2x-1)+(3x+2)+(2x-5))=0



We calculate terms in parentheses: -((2x-1)+(3x+2)+(2x-5)), so:

(2x-1)+(3x+2)+(2x-5)

We get rid of parentheses

2x+3x+2x-1+2-5

We add all the numbers together, and all the variables

7x-4

Back to the equation:

-(7x-4)



We get rid of parentheses

-7x+4+59=0

We add all the numbers together, and all the variables

-7x+63=0

We move all terms containing x to the left, all other terms to the right

-7x=-63

x=-63/-7

x=+9

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