k+6=2-3(3k+2)

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Solution for k+6=2-3(3k+2) equation:



k+6=2-3(3k+2)
We move all terms to the left:
k+6-(2-3(3k+2))=0
We calculate terms in parentheses: -(2-3(3k+2)), so:
2-3(3k+2)
determiningTheFunctionDomain -3(3k+2)+2
We multiply parentheses
-9k-6+2
We add all the numbers together, and all the variables
-9k-4
Back to the equation:
-(-9k-4)
We get rid of parentheses
k+9k+4+6=0
We add all the numbers together, and all the variables
10k+10=0
We move all terms containing k to the left, all other terms to the right
10k=-10
k=-10/10
k=-1

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