590=1/2*(3x+11)(X+4)

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Solution for 590=1/2*(3x+11)(X+4) equation: 



590=1/2(3x+11)(x+4)

We move all terms to the left:

590-(1/2(3x+11)(x+4))=0



Domain of the equation: 2(3x+11)(x+4))!=0

x∈R



We multiply parentheses ..

-(1/2(+3x^2+12x+11x+44))+590=0

We multiply all the terms by the denominator


-(1+590*2(+3x^2+12x+11x+44))=0



We calculate terms in parentheses: -(1+590*2(+3x^2+12x+11x+44)), so:

1+590*2(+3x^2+12x+11x+44)

determiningTheFunctionDomain
590*2(+3x^2+12x+11x+44)+1

Wy multiply elements

1180x(++1

We use the square of the difference formula

1180x(+1

Back to the equation:

-(1180x(+1)



We add all the numbers together, and all the variables

-(1180x1=0

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