3(a+2)=2(a+1)=6

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Solution for 3(a+2)=2(a+1)=6 equation: 



3(a+2)=2(a+1)=6

We move all terms to the left:

3(a+2)-(2(a+1))=0

We multiply parentheses

3a-(2(a+1))+6=0



We calculate terms in parentheses: -(2(a+1)), so:

2(a+1)

We multiply parentheses

2a+2

Back to the equation:

-(2a+2)



We get rid of parentheses

3a-2a-2+6=0

We add all the numbers together, and all the variables

a+4=0

We move all terms containing a to the left, all other terms to the right

a=-4

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