57x2=+23

Solution for 57x2=+23 equation:

57x^2=+23

We move all terms to the left:

57x^2-(+23)=0

We add all the numbers together, and all the variables

57x^2-23=0

a = 57; b = 0; c = -23;
Δ = b2-4ac
Δ = 02-4·57·(-23)
Δ = 5244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5244}=\sqrt{4*1311}=\sqrt{4}*\sqrt{1311}=2\sqrt{1311}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{1311}}{2*57}=\frac{0-2\sqrt{1311}}{114}
=-\frac{2\sqrt{1311}}{114}
=-\frac{\sqrt{1311}}{57}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{1311}}{2*57}=\frac{0+2\sqrt{1311}}{114}
=\frac{2\sqrt{1311}}{114}
=\frac{\sqrt{1311}}{57}
$