4=4/5(3)+b

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Solution for 4=4/5(3)+b equation: 



4=4/5(3)+b

We move all terms to the left:

4-(4/5(3)+b)=0



Domain of the equation: 53+b)!=0

We move all terms containing b to the left, all other terms to the right

b)!=-53

b!=-53/1

b!=-53

b∈R



We add all the numbers together, and all the variables

-(+b+4/53)+4=0

We get rid of parentheses

-b+4-4/53=0

We multiply all the terms by the denominator


-b*53-4+4*53=0

We add all the numbers together, and all the variables

-b*53+208=0

Wy multiply elements

-53b+208=0

We move all terms containing b to the left, all other terms to the right

-53b=-208

b=-208/-53

b=3+49/53

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