57=-3v(4v+1)+2v

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Solution for 57=-3v(4v+1)+2v equation: 



57=-3v(4v+1)+2v

We move all terms to the left:

57-(-3v(4v+1)+2v)=0



We calculate terms in parentheses: -(-3v(4v+1)+2v), so:

-3v(4v+1)+2v

We add all the numbers together, and all the variables

2v-3v(4v+1)

We multiply parentheses

-12v^2+2v-3v

We add all the numbers together, and all the variables

-12v^2-1v

Back to the equation:

-(-12v^2-1v)



We get rid of parentheses

12v^2+1v+57=0

We add all the numbers together, and all the variables

12v^2+v+57=0

a = 12; b = 1; c = +57;
Δ = b2-4ac
Δ = 12-4·12·57
Δ = -2735
Delta is less than zero, so there is no solution for the equation

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