7x+6(2-x)+8=15+3(6+x)

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Solution for 7x+6(2-x)+8=15+3(6+x) equation: 



7x+6(2-x)+8=15+3(6+x)

We move all terms to the left:

7x+6(2-x)+8-(15+3(6+x))=0

We add all the numbers together, and all the variables

7x+6(-1x+2)-(15+3(x+6))+8=0

We multiply parentheses

7x-6x-(15+3(x+6))+12+8=0



We calculate terms in parentheses: -(15+3(x+6)), so:

15+3(x+6)

determiningTheFunctionDomain
3(x+6)+15

We multiply parentheses

3x+18+15

We add all the numbers together, and all the variables

3x+33

Back to the equation:

-(3x+33)



We add all the numbers together, and all the variables

x-(3x+33)+20=0

We get rid of parentheses

x-3x-33+20=0

We add all the numbers together, and all the variables

-2x-13=0

We move all terms containing x to the left, all other terms to the right

-2x=13

x=13/-2

x=-6+1/2

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