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57-9/x=3x
We move all terms to the left:
57-9/x-(3x)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
-3x-9/x+57=0
We multiply all the terms by the denominator
-3x*x+57*x-9=0
We add all the numbers together, and all the variables
57x-3x*x-9=0
Wy multiply elements
-3x^2+57x-9=0
a = -3; b = 57; c = -9;
Δ = b2-4ac
Δ = 572-4·(-3)·(-9)
Δ = 3141
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3141}=\sqrt{9*349}=\sqrt{9}*\sqrt{349}=3\sqrt{349}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-3\sqrt{349}}{2*-3}=\frac{-57-3\sqrt{349}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+3\sqrt{349}}{2*-3}=\frac{-57+3\sqrt{349}}{-6} $
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