1/4x=18-x

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Solution for 1/4x=18-x equation:



1/4x=18-x
We move all terms to the left:
1/4x-(18-x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
We add all the numbers together, and all the variables
1/4x-(-1x+18)=0
We get rid of parentheses
1/4x+1x-18=0
We multiply all the terms by the denominator
1x*4x-18*4x+1=0
Wy multiply elements
4x^2-72x+1=0
a = 4; b = -72; c = +1;
Δ = b2-4ac
Δ = -722-4·4·1
Δ = 5168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{5168}=\sqrt{16*323}=\sqrt{16}*\sqrt{323}=4\sqrt{323}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-4\sqrt{323}}{2*4}=\frac{72-4\sqrt{323}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+4\sqrt{323}}{2*4}=\frac{72+4\sqrt{323}}{8} $

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