56x+1,344x-21=35(40x+89)

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Solution for 56x+1,344x-21=35(40x+89) equation: 



56x+1.344x-21=35(40x+89)

We move all terms to the left:

56x+1.344x-21-(35(40x+89))=0

We add all the numbers together, and all the variables

57.344x-(35(40x+89))-21=0



We calculate terms in parentheses: -(35(40x+89)), so:

35(40x+89)

We multiply parentheses

1400x+3115

Back to the equation:

-(1400x+3115)



We get rid of parentheses

57.344x-1400x-3115-21=0

We add all the numbers together, and all the variables

-1342.656x-3136=0

We move all terms containing x to the left, all other terms to the right

-1342.656x=3136

x=3136/-1342.656

x=-2+167.66666666666/499.49999999998

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