3(3x-2)=4(2+4x)

Solution for 3(3x-2)=4(2+4x) equation:

3(3x-2)=4(2+4x)

We move all terms to the left:

3(3x-2)-(4(2+4x))=0

We add all the numbers together, and all the variables

3(3x-2)-(4(4x+2))=0

We multiply parentheses

9x-(4(4x+2))-6=0


We calculate terms in parentheses: -(4(4x+2)), so:

4(4x+2)

We multiply parentheses

16x+8

Back to the equation:

-(16x+8)


We get rid of parentheses

9x-16x-8-6=0

We add all the numbers together, and all the variables

-7x-14=0

We move all terms containing x to the left, all other terms to the right

-7x=14

x=14/-7

x=-2