x(x+94)+(-10+x)=180

Solution for x(x+94)+(-10+x)=180 equation:

x(x+94)+(-10+x)=180

We move all terms to the left:

x(x+94)+(-10+x)-(180)=0

We add all the numbers together, and all the variables

x(x+94)+(x-10)-180=0

We multiply parentheses

x^2+94x+(x-10)-180=0

We get rid of parentheses

x^2+94x+x-10-180=0

We add all the numbers together, and all the variables

x^2+95x-190=0

a = 1; b = 95; c = -190;
Δ = b2-4ac
Δ = 952-4·1·(-190)
Δ = 9785
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(95)-\sqrt{9785}}{2*1}=\frac{-95-\sqrt{9785}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(95)+\sqrt{9785}}{2*1}=\frac{-95+\sqrt{9785}}{2}
$