56=4x-4(4x+7)

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Solution for 56=4x-4(4x+7) equation: 



56=4x-4(4x+7)

We move all terms to the left:

56-(4x-4(4x+7))=0



We calculate terms in parentheses: -(4x-4(4x+7)), so:

4x-4(4x+7)

We multiply parentheses

4x-16x-28

We add all the numbers together, and all the variables

-12x-28

Back to the equation:

-(-12x-28)



We get rid of parentheses

12x+28+56=0

We add all the numbers together, and all the variables

12x+84=0

We move all terms containing x to the left, all other terms to the right

12x=-84

x=-84/12

x=-7

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