(5x+2)*(5x+2)=0

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Solution for (5x+2)*(5x+2)=0 equation: 



(5x+2)(5x+2)=0

We multiply parentheses ..

(+25x^2+10x+10x+4)=0

We get rid of parentheses

25x^2+10x+10x+4=0

We add all the numbers together, and all the variables

25x^2+20x+4=0

a = 25; b = 20; c = +4;
Δ = b2-4ac
Δ = 202-4·25·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-20}{50}=-2/5$

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