56=2(2x-1)-6(1+6x)

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Solution for 56=2(2x-1)-6(1+6x) equation: 



56=2(2x-1)-6(1+6x)

We move all terms to the left:

56-(2(2x-1)-6(1+6x))=0

We add all the numbers together, and all the variables

-(2(2x-1)-6(6x+1))+56=0



We calculate terms in parentheses: -(2(2x-1)-6(6x+1)), so:

2(2x-1)-6(6x+1)

We multiply parentheses

4x-36x-2-6

We add all the numbers together, and all the variables

-32x-8

Back to the equation:

-(-32x-8)



We get rid of parentheses

32x+8+56=0

We add all the numbers together, and all the variables

32x+64=0

We move all terms containing x to the left, all other terms to the right

32x=-64

x=-64/32

x=-2

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