2n+5(n+2)-7=2(4n-2)-n+7

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Solution for 2n+5(n+2)-7=2(4n-2)-n+7 equation: 



2n+5(n+2)-7=2(4n-2)-n+7

We move all terms to the left:

2n+5(n+2)-7-(2(4n-2)-n+7)=0

We multiply parentheses

2n+5n-(2(4n-2)-n+7)+10-7=0



We calculate terms in parentheses: -(2(4n-2)-n+7), so:

2(4n-2)-n+7

We add all the numbers together, and all the variables

-1n+2(4n-2)+7

We multiply parentheses

-1n+8n-4+7

We add all the numbers together, and all the variables

7n+3

Back to the equation:

-(7n+3)



We add all the numbers together, and all the variables

7n-(7n+3)+3=0

We get rid of parentheses

7n-7n-3+3=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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