56-(3c-4)=4(c+5)+6

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Solution for 56-(3c-4)=4(c+5)+6 equation: 



56-(3c-4)=4(c+5)+6

We move all terms to the left:

56-(3c-4)-(4(c+5)+6)=0

We get rid of parentheses

-3c-(4(c+5)+6)+4+56=0



We calculate terms in parentheses: -(4(c+5)+6), so:

4(c+5)+6

We multiply parentheses

4c+20+6

We add all the numbers together, and all the variables

4c+26

Back to the equation:

-(4c+26)



We add all the numbers together, and all the variables

-3c-(4c+26)+60=0

We get rid of parentheses

-3c-4c-26+60=0

We add all the numbers together, and all the variables

-7c+34=0

We move all terms containing c to the left, all other terms to the right

-7c=-34

c=-34/-7

c=4+6/7

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