-3x-4(4x-8)+10=3(-8x-1)+10

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Solution for -3x-4(4x-8)+10=3(-8x-1)+10 equation: 



-3x-4(4x-8)+10=3(-8x-1)+10

We move all terms to the left:

-3x-4(4x-8)+10-(3(-8x-1)+10)=0

We multiply parentheses

-3x-16x-(3(-8x-1)+10)+32+10=0



We calculate terms in parentheses: -(3(-8x-1)+10), so:

3(-8x-1)+10

We multiply parentheses

-24x-3+10

We add all the numbers together, and all the variables

-24x+7

Back to the equation:

-(-24x+7)



We add all the numbers together, and all the variables

-19x-(-24x+7)+42=0

We get rid of parentheses

-19x+24x-7+42=0

We add all the numbers together, and all the variables

5x+35=0

We move all terms containing x to the left, all other terms to the right

5x=-35

x=-35/5

x=-7

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