5(b+1)=4(b-1)

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Solution for 5(b+1)=4(b-1) equation: 



5(b+1)=4(b-1)

We move all terms to the left:

5(b+1)-(4(b-1))=0

We multiply parentheses

5b-(4(b-1))+5=0



We calculate terms in parentheses: -(4(b-1)), so:

4(b-1)

We multiply parentheses

4b-4

Back to the equation:

-(4b-4)



We get rid of parentheses

5b-4b+4+5=0

We add all the numbers together, and all the variables

b+9=0

We move all terms containing b to the left, all other terms to the right

b=-9

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