p2-64=(p+8)(p-8)

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Solution for p2-64=(p+8)(p-8) equation: 



p2-64=(p+8)(p-8)

We move all terms to the left:

p2-64-((p+8)(p-8))=0

We add all the numbers together, and all the variables

p^2-((p+8)(p-8))-64=0

We use the square of the difference formula

p^2+p^2+64-64=0

We add all the numbers together, and all the variables

2p^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{4}=0$

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