54(b-2)-10=2(b+3)

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Solution for 54(b-2)-10=2(b+3) equation: 



54(b-2)-10=2(b+3)

We move all terms to the left:

54(b-2)-10-(2(b+3))=0

We multiply parentheses

54b-(2(b+3))-108-10=0



We calculate terms in parentheses: -(2(b+3)), so:

2(b+3)

We multiply parentheses

2b+6

Back to the equation:

-(2b+6)



We add all the numbers together, and all the variables

54b-(2b+6)-118=0

We get rid of parentheses

54b-2b-6-118=0

We add all the numbers together, and all the variables

52b-124=0

We move all terms containing b to the left, all other terms to the right

52b=124

b=124/52

b=2+5/13

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