40-(3x+4)=x+4(x+5)

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Solution for 40-(3x+4)=x+4(x+5) equation: 



40-(3x+4)=x+4(x+5)

We move all terms to the left:

40-(3x+4)-(x+4(x+5))=0

We get rid of parentheses

-3x-(x+4(x+5))-4+40=0



We calculate terms in parentheses: -(x+4(x+5)), so:

x+4(x+5)

We multiply parentheses

x+4x+20

We add all the numbers together, and all the variables

5x+20

Back to the equation:

-(5x+20)



We add all the numbers together, and all the variables

-3x-(5x+20)+36=0

We get rid of parentheses

-3x-5x-20+36=0

We add all the numbers together, and all the variables

-8x+16=0

We move all terms containing x to the left, all other terms to the right

-8x=-16

x=-16/-8

x=+2

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