51=3(27+2z)

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Solution for 51=3(27+2z) equation:



51=3(27+2z)
We move all terms to the left:
51-(3(27+2z))=0
We add all the numbers together, and all the variables
-(3(2z+27))+51=0
We calculate terms in parentheses: -(3(2z+27)), so:
3(2z+27)
We multiply parentheses
6z+81
Back to the equation:
-(6z+81)
We get rid of parentheses
-6z-81+51=0
We add all the numbers together, and all the variables
-6z-30=0
We move all terms containing z to the left, all other terms to the right
-6z=30
z=30/-6
z=-5

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