30m2-77m+48=0

Solution for 30m2-77m+48=0 equation:

30m^2-77m+48=0

a = 30; b = -77; c = +48;
Δ = b2-4ac
Δ = -772-4·30·48
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-77)-13}{2*30}=\frac{64}{60}
=1+1/15
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-77)+13}{2*30}=\frac{90}{60}
=1+1/2
$