510x+510x+5610=17x(x+11)

Solution for 510x+510x+5610=17x(x+11) equation:

510x+510x+5610=17x(x+11)

We move all terms to the left:

510x+510x+5610-(17x(x+11))=0

We add all the numbers together, and all the variables

1020x-(17x(x+11))+5610=0


We calculate terms in parentheses: -(17x(x+11)), so:

17x(x+11)

We multiply parentheses

17x^2+187x

Back to the equation:

-(17x^2+187x)


We get rid of parentheses

-17x^2+1020x-187x+5610=0

We add all the numbers together, and all the variables

-17x^2+833x+5610=0

a = -17; b = 833; c = +5610;
Δ = b2-4ac
Δ = 8332-4·(-17)·5610
Δ = 1075369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1075369}=1037$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(833)-1037}{2*-17}=\frac{-1870}{-34}
=+55
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(833)+1037}{2*-17}=\frac{204}{-34}
=-6
$