510x+510x+5610=7x(x+11)

Solution for 510x+510x+5610=7x(x+11) equation:

510x+510x+5610=7x(x+11)

We move all terms to the left:

510x+510x+5610-(7x(x+11))=0

We add all the numbers together, and all the variables

1020x-(7x(x+11))+5610=0


We calculate terms in parentheses: -(7x(x+11)), so:

7x(x+11)

We multiply parentheses

7x^2+77x

Back to the equation:

-(7x^2+77x)


We get rid of parentheses

-7x^2+1020x-77x+5610=0

We add all the numbers together, and all the variables

-7x^2+943x+5610=0

a = -7; b = 943; c = +5610;
Δ = b2-4ac
Δ = 9432-4·(-7)·5610
Δ = 1046329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(943)-\sqrt{1046329}}{2*-7}=\frac{-943-\sqrt{1046329}}{-14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(943)+\sqrt{1046329}}{2*-7}=\frac{-943+\sqrt{1046329}}{-14}
$