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51/2a+17=5a+12
We move all terms to the left:
51/2a+17-(5a+12)=0
Domain of the equation: 2a!=0We get rid of parentheses
a!=0/2
a!=0
a∈R
51/2a-5a-12+17=0
We multiply all the terms by the denominator
-5a*2a-12*2a+17*2a+51=0
Wy multiply elements
-10a^2-24a+34a+51=0
We add all the numbers together, and all the variables
-10a^2+10a+51=0
a = -10; b = 10; c = +51;
Δ = b2-4ac
Δ = 102-4·(-10)·51
Δ = 2140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2140}=\sqrt{4*535}=\sqrt{4}*\sqrt{535}=2\sqrt{535}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{535}}{2*-10}=\frac{-10-2\sqrt{535}}{-20} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{535}}{2*-10}=\frac{-10+2\sqrt{535}}{-20} $
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