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50x^2=500
We move all terms to the left:
50x^2-(500)=0
a = 50; b = 0; c = -500;
Δ = b2-4ac
Δ = 02-4·50·(-500)
Δ = 100000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{100000}=\sqrt{10000*10}=\sqrt{10000}*\sqrt{10}=100\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-100\sqrt{10}}{2*50}=\frac{0-100\sqrt{10}}{100} =-\frac{100\sqrt{10}}{100} =-\sqrt{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+100\sqrt{10}}{2*50}=\frac{0+100\sqrt{10}}{100} =\frac{100\sqrt{10}}{100} =\sqrt{10} $
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