3*(3x-1)+1=x-2*(2-x)

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Solution for 3*(3x-1)+1=x-2*(2-x) equation: 



3(3x-1)+1=x-2(2-x)

We move all terms to the left:

3(3x-1)+1-(x-2(2-x))=0

We add all the numbers together, and all the variables

3(3x-1)-(x-2(-1x+2))+1=0

We multiply parentheses

9x-(x-2(-1x+2))-3+1=0



We calculate terms in parentheses: -(x-2(-1x+2)), so:

x-2(-1x+2)

We multiply parentheses

x+2x-4

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We add all the numbers together, and all the variables

9x-(3x-4)-2=0

We get rid of parentheses

9x-3x+4-2=0

We add all the numbers together, and all the variables

6x+2=0

We move all terms containing x to the left, all other terms to the right

6x=-2

x=-2/6

x=-1/3

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