50=x(x-2)+x+2x+8

Solution for 50=x(x-2)+x+2x+8 equation:

50=x(x-2)+x+2x+8

We move all terms to the left:

50-(x(x-2)+x+2x+8)=0


We calculate terms in parentheses: -(x(x-2)+x+2x+8), so:

x(x-2)+x+2x+8

We add all the numbers together, and all the variables

3x+x(x-2)+8

We multiply parentheses

x^2+3x-2x+8

We add all the numbers together, and all the variables

x^2+x+8

Back to the equation:

-(x^2+x+8)


We get rid of parentheses

-x^2-x-8+50=0

We add all the numbers together, and all the variables

-1x^2-1x+42=0

a = -1; b = -1; c = +42;
Δ = b2-4ac
Δ = -12-4·(-1)·42
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-13}{2*-1}=\frac{-12}{-2}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+13}{2*-1}=\frac{14}{-2}
=-7
$