(2-x)(1-x)+0.25=0

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Solution for (2-x)(1-x)+0.25=0 equation: 



(2-x)(1-x)+0.25=0

We add all the numbers together, and all the variables

(-1x+2)(-1x+1)+0.25=0

We multiply parentheses ..

(+x^2-1x-2x+2)+0.25=0

We get rid of parentheses

x^2-1x-2x+2+0.25=0

We add all the numbers together, and all the variables

x^2-3x+2.25=0

a = 1; b = -3; c = +2.25;
Δ = b2-4ac
Δ = -32-4·1·2.25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{3}{2}=1+1/2$

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