50=-2(23-b)+4(b-3)

Solution for 50=-2(23-b)+4(b-3) equation:

50=-2(23-b)+4(b-3)

We move all terms to the left:

50-(-2(23-b)+4(b-3))=0

We add all the numbers together, and all the variables

-(-2(-1b+23)+4(b-3))+50=0


We calculate terms in parentheses: -(-2(-1b+23)+4(b-3)), so:

-2(-1b+23)+4(b-3)

We multiply parentheses

2b+4b-46-12

We add all the numbers together, and all the variables

6b-58

Back to the equation:

-(6b-58)


We get rid of parentheses

-6b+58+50=0

We add all the numbers together, and all the variables

-6b+108=0

We move all terms containing b to the left, all other terms to the right

-6b=-108

b=-108/-6

b=+18