2(z+4)-3=1/2(10+4z)

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Solution for 2(z+4)-3=1/2(10+4z) equation: 



2(z+4)-3=1/2(10+4z)

We move all terms to the left:

2(z+4)-3-(1/2(10+4z))=0



Domain of the equation: 2(10+4z))!=0

z∈R



We add all the numbers together, and all the variables

2(z+4)-(1/2(4z+10))-3=0

We multiply parentheses

2z-(1/2(4z+10))+8-3=0

We multiply all the terms by the denominator


2z*2(4z+10))-(1+8*2(4z+10))-3*2(4z+10))=0

We add all the numbers together, and all the variables

2z*2(4z+10))-(1+8*2(4z+10))-3*2(4z=0

Wy multiply elements

4z^2(4+32z^2(4=0

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