39=2c-3(6c-3)

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Solution for 39=2c-3(6c-3) equation: 



39=2c-3(6c-3)

We move all terms to the left:

39-(2c-3(6c-3))=0



We calculate terms in parentheses: -(2c-3(6c-3)), so:

2c-3(6c-3)

We multiply parentheses

2c-18c+9

We add all the numbers together, and all the variables

-16c+9

Back to the equation:

-(-16c+9)



We get rid of parentheses

16c-9+39=0

We add all the numbers together, and all the variables

16c+30=0

We move all terms containing c to the left, all other terms to the right

16c=-30

c=-30/16

c=-1+7/8

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