50=(9/5)(c)+32

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Solution for 50=(9/5)(c)+32 equation: 



50=(9/5)(c)+32

We move all terms to the left:

50-((9/5)(c)+32)=0



Domain of the equation: 5)c+32)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

-((+9/5)c+32)+50=0

We multiply all the terms by the denominator


-((+9+50*5)c+32)=0



We calculate terms in parentheses: -((+9+50*5)c+32), so:

(+9+50*5)c+32

We add all the numbers together, and all the variables

259c+32

Back to the equation:

-(259c+32)



We get rid of parentheses

-259c-32=0

We move all terms containing c to the left, all other terms to the right

-259c=32

c=32/-259

c=-32/259

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