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5(2x-6)=6-6(3x-1)
We move all terms to the left:
5(2x-6)-(6-6(3x-1))=0
We multiply parentheses
10x-(6-6(3x-1))-30=0
We calculate terms in parentheses: -(6-6(3x-1)), so:We get rid of parentheses
6-6(3x-1)
determiningTheFunctionDomain -6(3x-1)+6
We multiply parentheses
-18x+6+6
We add all the numbers together, and all the variables
-18x+12
Back to the equation:
-(-18x+12)
10x+18x-12-30=0
We add all the numbers together, and all the variables
28x-42=0
We move all terms containing x to the left, all other terms to the right
28x=42
x=42/28
x=1+1/2
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