50=(60p+40(1-p))/1.06

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Solution for 50=(60p+40(1-p))/1.06 equation: 



50=(60p+40(1-p))/1.06

We move all terms to the left:

50-((60p+40(1-p))/1.06)=0

We add all the numbers together, and all the variables

-((60p+40(-1p+1))/1.06)+50=0

We multiply all the terms by the denominator


-((60p+40(-1p+1))+50*1.06)=0



We calculate terms in parentheses: -((60p+40(-1p+1))+50*1.06), so:

(60p+40(-1p+1))+50*1.06

We add all the numbers together, and all the variables

(60p+40(-1p+1))+53



We calculate terms in parentheses: +(60p+40(-1p+1)), so:

60p+40(-1p+1)

We multiply parentheses

60p-40p+40

We add all the numbers together, and all the variables

20p+40

Back to the equation:

+(20p+40)



We get rid of parentheses

20p+40+53

We add all the numbers together, and all the variables

20p+93

Back to the equation:

-(20p+93)



We get rid of parentheses

-20p-93=0

We move all terms containing p to the left, all other terms to the right

-20p=93

p=93/-20

p=-4+13/20

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