50=(2x+14)(x+2)

Solution for 50=(2x+14)(x+2) equation:

50=(2x+14)(x+2)

We move all terms to the left:

50-((2x+14)(x+2))=0

We multiply parentheses ..

-((+2x^2+4x+14x+28))+50=0


We calculate terms in parentheses: -((+2x^2+4x+14x+28)), so:

(+2x^2+4x+14x+28)

We get rid of parentheses

2x^2+4x+14x+28

We add all the numbers together, and all the variables

2x^2+18x+28

Back to the equation:

-(2x^2+18x+28)


We get rid of parentheses

-2x^2-18x-28+50=0

We add all the numbers together, and all the variables

-2x^2-18x+22=0

a = -2; b = -18; c = +22;
Δ = b2-4ac
Δ = -182-4·(-2)·22
Δ = 500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{500}=\sqrt{100*5}=\sqrt{100}*\sqrt{5}=10\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-10\sqrt{5}}{2*-2}=\frac{18-10\sqrt{5}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+10\sqrt{5}}{2*-2}=\frac{18+10\sqrt{5}}{-4}
$