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5/x+3=8/2x
We move all terms to the left:
5/x+3-(8/2x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
5/x-(+8/2x)+3=0
We get rid of parentheses
5/x-8/2x+3=0
We calculate fractions
10x/2x^2+(-8x)/2x^2+3=0
We multiply all the terms by the denominator
10x+(-8x)+3*2x^2=0
Wy multiply elements
6x^2+10x+(-8x)=0
We get rid of parentheses
6x^2+10x-8x=0
We add all the numbers together, and all the variables
6x^2+2x=0
a = 6; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·6·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*6}=\frac{-4}{12} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*6}=\frac{0}{12} =0 $
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