5/8x+8/40x=66

Solution for 5/8x+8/40x=66 equation:

5/8x+8/40x=66

We move all terms to the left:

5/8x+8/40x-(66)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 40x!=0

x!=0/40

x!=0

x∈R


We calculate fractions


200x/320x^2+64x/320x^2-66=0

We multiply all the terms by the denominator


200x+64x-66*320x^2=0

We add all the numbers together, and all the variables

264x-66*320x^2=0

Wy multiply elements

-21120x^2+264x=0

a = -21120; b = 264; c = 0;
Δ = b2-4ac
Δ = 2642-4·(-21120)·0
Δ = 69696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{69696}=264$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(264)-264}{2*-21120}=\frac{-528}{-42240}
=1/80
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(264)+264}{2*-21120}=\frac{0}{-42240}
=0
$