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5/8x+3/4x=11
We move all terms to the left:
5/8x+3/4x-(11)=0
Domain of the equation: 8x!=0
x!=0/8
x!=0
x∈R
Domain of the equation: 4x!=0We calculate fractions
x!=0/4
x!=0
x∈R
20x/32x^2+24x/32x^2-11=0
We multiply all the terms by the denominator
20x+24x-11*32x^2=0
We add all the numbers together, and all the variables
44x-11*32x^2=0
Wy multiply elements
-352x^2+44x=0
a = -352; b = 44; c = 0;
Δ = b2-4ac
Δ = 442-4·(-352)·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-44}{2*-352}=\frac{-88}{-704} =1/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+44}{2*-352}=\frac{0}{-704} =0 $
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