5/8h+3/4h=11

Solution for 5/8h+3/4h=11 equation:

5/8h+3/4h=11

We move all terms to the left:

5/8h+3/4h-(11)=0


Domain of the equation: 8h!=0

h!=0/8

h!=0

h∈R



Domain of the equation: 4h!=0

h!=0/4

h!=0

h∈R


We calculate fractions


20h/32h^2+24h/32h^2-11=0

We multiply all the terms by the denominator


20h+24h-11*32h^2=0

We add all the numbers together, and all the variables

44h-11*32h^2=0

Wy multiply elements

-352h^2+44h=0

a = -352; b = 44; c = 0;
Δ = b2-4ac
Δ = 442-4·(-352)·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-44}{2*-352}=\frac{-88}{-704}
=1/8
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+44}{2*-352}=\frac{0}{-704}
=0
$