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5/8x+20=2(x-16)
We move all terms to the left:
5/8x+20-(2(x-16))=0
Domain of the equation: 8x!=0We multiply all the terms by the denominator
x!=0/8
x!=0
x∈R
-((2(x-16)))*8x+20*8x+5=0
Wy multiply elements
-((2(x-16)))*8x+160x+5=0
We add all the numbers together, and all the variables
160x-((2(x-16)))*8x+5=0
We move all terms containing x to the left, all other terms to the right
160x-((2(x-16)))*8x=-5
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