276=(x+8)+(x+5)+(2x-1)

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Solution for 276=(x+8)+(x+5)+(2x-1) equation: 



276=(x+8)+(x+5)+(2x-1)

We move all terms to the left:

276-((x+8)+(x+5)+(2x-1))=0



We calculate terms in parentheses: -((x+8)+(x+5)+(2x-1)), so:

(x+8)+(x+5)+(2x-1)

We get rid of parentheses

x+x+2x+8+5-1

We add all the numbers together, and all the variables

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

-4x-12+276=0

We add all the numbers together, and all the variables

-4x+264=0

We move all terms containing x to the left, all other terms to the right

-4x=-264

x=-264/-4

x=+66

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